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## If the length of a rectangular field is increased by 20% and the breadth is reduced by 20%, the area of the rectangle will be 192 m2. What is the area of the original rectangle ?

(a) 184 m2
(b) 196 m2
(c) 198 m2
(d) 200 m2

Let the length and breadth of the original rectangle be L m and B m respectively.

After increasing the length by 20% and decreasing breadth by 20% area is 192

(1.2 L) X (0.8 B) = 192

or 0.96 LB = 192

LB = 200

## 456 X 456 – 302 X 302

(a) 128734
(b) 118564
(c) 116732
(d) 127856

=456 X 456 – 302 X 302

=(456)2 – (302)2

=(456+302) – (456-302) Formula [a2 – b2=(a+b)(a-b)]

=758 X 154

=116732

## The sum of three consecutive numbers is 93. The greatest among these three numbers is

(a) 27

(b) 28

(c) 30

(d) 32

Let the three numbers are x, x+1 and x+2

Then x+(x+1)+(x+2)=93

3x=90

x=30

Greater Number=(x+2)=32

## The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:

 A. 200 m B. 225 m C. 245 m D. 250 m

Explanation:

 Speed = 45 x 5 m/sec = 25 m/sec. 18 2

Time = 30 sec.

Let the length of bridge be x metres.

 Then, 130 + x = 25 30 2

2(130 + x) = 750

x = 245 m.

## A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?

 A. 45 km/hr B. 50 km/hr C. 54 km/hr D. 55 km/hr

Explanation:

 Speed of the train relative to man = 125 m/sec 10
 = 25 m/sec. 2
 = 25 x 18 km/hr 2 5

= 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr.

x – 5 = 45          x = 50 km/hr.